Book Image

PHP 7 Data Structures and Algorithms

By : Mizanur Rahman
5 (1)
Book Image

PHP 7 Data Structures and Algorithms

5 (1)
By: Mizanur Rahman

Overview of this book

PHP has always been the the go-to language for web based application development, but there are materials and resources you can refer to to see how it works. Data structures and algorithms help you to code and execute them effectively, cutting down on processing time significantly. If you want to explore data structures and algorithms in a practical way with real-life projects, then this book is for you. The book begins by introducing you to data structures and algorithms and how to solve a problem from beginning to end using them. Once you are well aware of the basics, it covers the core aspects like arrays, listed lists, stacks and queues. It will take you through several methods of finding efficient algorithms and show you which ones you should implement in each scenario. In addition to this, you will explore the possibilities of functional data structures using PHP and go through advanced algorithms and graphs as well as dynamic programming. By the end, you will be confident enough to tackle both basic and advanced data structures, understand how they work, and know when to use them in your day-to-day work
Table of Contents (14 chapters)

Shortest path using the Floyd-Warshall algorithm

A common scenario for a pizza-delivery company is to deliver the pizza as quickly as possible. Graph algorithms can help us in such situations. The Floyd-Warshall algorithm is a very common algorithm that is used to find the shortest path from u to v using all pairs of vertices (u, v). The shortest path indicates the shortest possible distance between two nodes that are interconnected. The graph for calculating the shortest path has to be a weighted graph. In some cases, the weight can be negative as well. The algorithm is very simple and one of the easiest to implement. It is shown here:

for i:= 1 to n do 
for j:= 1 to n do
dis[i][j] = w[i][j]

for k:= 1 to n do
for i:= 1 to n do
for j:= 1 to n do
sum := dis[i][k] + dis[k][j]
if (sum < dis[i][j])
dis[i][j] := sum

First, we...