Book Image

Learn Red ? Fundamentals of Red

By : Ivo Balbaert
Book Image

Learn Red ? Fundamentals of Red

By: Ivo Balbaert

Overview of this book

A key problem of software development today is software bloat, where huge toolchains and development environments are needed in software coding and deployment. Red significantly reduces this bloat by offering a minimalist but complete toolchain. This is the first introductory book about it, and it will get you up and running with Red as quickly as possible. This book shows you how to write effective functions, reduce code redundancies, and improve code reuse. It will be helpful for new programmers who are starting out with Red to explore its wide and ever-growing package ecosystem and also for experienced developers who want to add Red to their skill set. The book presents the fundamentals of programming in Red and in-depth informative examples using a step-by-step approach. You will be taken through concepts and examples such as doing simple metaprogramming, functions, collections, GUI applications, and more. By the end of the book, you will be fully equipped to start your own projects in Red.
Table of Contents (13 chapters)
11
Assessments

Questions

  1. Make a bitset to store all lowercase letters and another for all uppercase letters.
  2. Use union to make a bitset storing all alphanumerical characters.
  3. Use union to make a bitset storing all characters used in hexadecimal numbers.
  4. Make a rules pattern integer to match with integer numbers, starting optionally with a + or - sign.
  5. Make a pattern that matches the following product codes: "#ABC-nnnn" or "#XYZ-nnnn", where nnnn is a four-digit pattern.
  6. Try for yourself to parse the data string to extract the exchange rate 0.81191502. (Hint: use some and the letter charset.)
  7. Starting with rate: "<title>1 USD = 0.81191502 EUR</title>", change both tags to <rate> tags, by using two rules.
  8. Use parse and the code within it to obtain the exchange rate info in this form: [ "EUR" 0.81191502 "GPB" 0.70675954 ......