Book Image

Modern Python Standard Library Cookbook

By : Alessandro Molina
Book Image

Modern Python Standard Library Cookbook

By: Alessandro Molina

Overview of this book

The Python 3 Standard Library is a vast array of modules that you can use for developing various kinds of applications. It contains an exhaustive list of libraries, and this book will help you choose the best one to address specific programming problems in Python. The Modern Python Standard Library Cookbook begins with recipes on containers and data structures and guides you in performing effective text management in Python. You will find Python recipes for command-line operations, networking, filesystems and directories, and concurrent execution. You will learn about Python security essentials in Python and get to grips with various development tools for debugging, benchmarking, inspection, error reporting, and tracing. The book includes recipes to help you create graphical user interfaces for your application. You will learn to work with multimedia components and perform mathematical operations on date and time. The recipes will also show you how to deploy different searching and sorting algorithms on your data. By the end of the book, you will have acquired the skills needed to write clean code in Python and develop applications that meet your needs.
Table of Contents (21 chapters)
Title Page
Copyright and Credits
Packt Upsell
Contributors
Preface
Index

Zipping


Zipping means attaching two different iterables to create a new one that contains values from both.

This is very convenient when you have multiple tracks of values that should proceed concurrently. Imagine you had names and surnames and you want to just get a list of people:

names = [ 'Sam', 'Axel', 'Aerith' ]
surnames = [ 'Fisher', 'Foley', 'Gainsborough' ]

How to do it...

We want to zip together names and surnames:

>>> people = zip(names, surnames)
>>> list(people)
[('Sam', 'Fisher'), ('Axel', 'Foley'), ('Aerith', 'Gainsborough')]

How it works...

Zip will make a new iterable where each item in the newly-created iterable is a collection that is made by picking one item for each one of the provided iterables.

So, result[0] = (i[0], j[0]), and result[1] = (i[1], j[1]), and so on. If i and j have different lengths, it will stop as soon as one of the two is exhausted.

If you want to proceed until you exhaust the longest one of the provided iterables instead of stopping on the...