In R functions, the arguments are the input variables supplied when you invoke the function. We can pass the argument, named argument, argument with default variable, or unspecific numbers of argument into functions. In this recipe, we will demonstrate how to pass different kinds of arguments to our defined function.
Perform the following steps to create a function with different types of argument lists:
Type the following code to your R console to create a function with a default value:
>defaultarg<- function(x, y = 5){ + y <- y * 2 + s <- x+y + return(s) + }
Then, execute the
defaultarguser-defined function by passing3as the input argument:>defaultarg(3) [1] 13
Alternatively, you can pass different types of input argument to the function:
>defaultarg(1:3) [1] 11 12 13
You can also pass two arguments into the function:
>defaultarg(3,6) [1] 15
Or, you can pass a named argument list into the function:
>defaultarg(y = 6, x = 3) [1] 15
Moving on, you can use if-else-condition together with the function of the named argument:
>funcarg<- function(x, y, type= "sum"){ + if (type == "sum"){ + sum(x,y) + }else if (type == "mean"){ + mean(x,y) + }else{ + x * y + } + } >funcarg(3,5) [1] 8 >funcarg(3,5, type = 'mean') [1] 3 >funcarg(3,5, type = 'unknown') [1] 15
Additionally, one can pass an unspecified number of parameters to the function:
>unspecarg<- function(x, y, ...){ + x <- x + 2 + y <- y * 2 + sum(x,y, ...) + } >unspecarg(3,5) [1] 15 >unspecarg(3,5,7,9,11) [1] 42
R provides a flexible argument binding mechanism when creating functions. In this recipe, we first create a function called defaultag with two formal arguments: x and y. Here, the y argument has a default value, defined as 5. Then, when we make a function call by passing 3 to defaultarg, it passes 3 to x and 5 to y in the function and returns 13. Besides passing a scalar as the function input, we can pass a vector (or any other data type) to the function. In this example, if we pass a 1:3 vector to defaultarg, it returns a vector.
Moving on, we can see how arguments bind to the function. When calling a function by passing an argument without a parameter name, the function binds the passing value by position. Take step 4 as an example; the first 3 argument matches to x, and 6 matches to y, and it returns 15. On the other hand, you can pass arguments by name. In step 5, we can pass named arguments to the function in any order. Thus, if we pass y=6 and x=3 to defaultarg, the function returns 15.
Furthermore, we can use an argument as a control statement. In step 6, we specify three formal arguments: x, y, and type, in which the type argument has the default value defined as sum. Next, we can specify the value for the type argument as a condition in the if-else control flow. That is, when we pass sum to type, it returns the summation of x and y. When we pass mean to type, it returns the average of x and y. When we pass any value other than sum and mean to the type argument, it returns the product of x and y.
Lastly, we can pass an unspecified number of arguments to the function using the ... notation. In the final step of this example, if we pass only 3 and 5 to the function, the function first passes 3 to x and 5 to y. Then, the function adds 2 to x, multiplies y by 2, and sums the value of both x and y. However, if we pass more than two arguments to the function, the function will also sum the additional parameters.
In addition to giving a full argument name, we can abbreviate the argument name when making a function call:
>funcarg(3,5, t = 'unknown') [1] 15
Here, though we do not specify the argument's name, type, correctly, the function passes a value of unknown to the argument type, and returns 15 as the output.