Book Image

Learn C Programming

By : Jeff Szuhay
Book Image

Learn C Programming

By: Jeff Szuhay

Overview of this book

C is a powerful general-purpose programming language that is excellent for beginners to learn. This book will introduce you to computer programming and software development using C. If you're an experienced developer, this book will help you to become familiar with the C programming language. This C programming book takes you through basic programming concepts and shows you how to implement them in C. Throughout the book, you'll create and run programs that make use of one or more C concepts, such as program structure with functions, data types, and conditional statements. You'll also see how to use looping and iteration, arrays, pointers, and strings. As you make progress, you'll cover code documentation, testing and validation methods, basic input/output, and how to write complete programs in C. By the end of the book, you'll have developed basic programming skills in C, that you can apply to other programming languages and will develop a solid foundation for you to advance as a programmer.
Table of Contents (33 chapters)
Section 1: C Fundamentals
Section 2: Complex Data Types
Section 3: Memory Manipulation
Section 4: Input and Output
Section 5: Building Blocks for Larger Programs

Using explicit assignment, the simplest statement

We have already seen explicit assignment used when we initialized variables and constants. After we have declared a variable, we can change it by using the =assignment operator. An assignment statement is of the form identifier = value;, whereidentifieris our already-declared variable and the value can be a constant, another variable, the result of a calculation, or the returned value from a function. We will later see how all of these are expressions are evaluated and provide a result.

Here is an example of assignment statements:

feet = 24.75;

The 24.75literal constant is evaluated as a value of float or double type and is assigned to the feetvariable:

feet = yards/3.0 ;

The value of yards is obtained and then divided by the 3.0literal constant. The result of the evaluation is assigned to the feet variable. The value ofyardsis unchanged:

feet = inchesToFeet( inches );