Book Image

Modern C++: Efficient and Scalable Application Development

By : Richard Grimes, Marius Bancila
Book Image

Modern C++: Efficient and Scalable Application Development

By: Richard Grimes, Marius Bancila

Overview of this book

C++ is one of the most widely used programming languages. It is fast, flexible, and used to solve many programming problems. This Learning Path gives you an in-depth and hands-on experience of working with C++, using the latest recipes and understanding most recent developments. You will explore C++ programming constructs by learning about language structures, functions, and classes, which will help you identify the execution flow through code. You will also understand the importance of the C++ standard library as well as memory allocation for writing better and faster programs. Modern C++: Efficient and Scalable Application Development deals with the challenges faced with advanced C++ programming. You will work through advanced topics such as multithreading, networking, concurrency, lambda expressions, and many more recipes. By the end of this Learning Path, you will have all the skills to become a master C++ programmer. This Learning Path includes content from the following Packt products: • Beginning C++ Programming by Richard Grimes • Modern C++ Programming Cookbook by Marius Bancila • The Modern C++ Challenge by Marius Bancila
Table of Contents (24 chapters)
Title Page
Copyright
About Packt
Contributors
Preface
12
Math Problems
13
Language Features
14
Strings and Regular Expressions
15
Streams and Filesystems
16
Date and Time
17
Algorithms and Data Structures
Index

Solutions


Here are the solutions for the above problem-solving sections.

32. Pascal's triangle

Pascal's triangle is a construction representing binomial coefficients. The triangle starts with a row that has a single value of 1. Elements of each row are constructed by summing the numbers above, to the left and right, and treating blank entries as 0. Here is an example of the triangle with five rows:

        1
      1   1
    1   2   1
  1   3   3   1
1   4   6   4   1

To print the triangle, we must:

  • Shift the output position to the right with an appropriate number of spaces, so that the top is projected on the middle of the triangle's base.
  • Compute each value by summing the above left and right values. A simpler formula is that for a row i and column j, each new value x is equal to the previous value of x multiplied by (i - j) / (j + 1), where x starts at 1.

The following is a possible implementation of a function that prints the triangle:

unsigned int number_of_digits(unsigned int const i)
{
  ...