Book Image

MySQL 8 Cookbook

By : Karthik Appigatla
Book Image

MySQL 8 Cookbook

By: Karthik Appigatla

Overview of this book

MySQL is one of the most popular and widely used relational databases in the World today. The recently released MySQL 8 version promises to be better and more efficient than ever before. This book contains everything you need to know to be the go-to person in your organization when it comes to MySQL. Starting with a quick installation and configuration of your MySQL instance, the book quickly jumps into the querying aspects of MySQL. It shows you the newest improvements in MySQL 8 and gives you hands-on experience in managing high-transaction and real-time datasets. If you've already worked with MySQL before and are looking to migrate your application to MySQL 8, this book will also show you how to do that. The book also contains recipes on efficient MySQL administration, with tips on effective user management, data recovery, security, database monitoring, performance tuning, troubleshooting, and more. With quick solutions to common and not-so-common problems you might encounter while working with MySQL 8, the book contains practical tips and tricks to give you the edge over others in designing, developing, and administering your database effectively.
Table of Contents (20 chapters)
Title Page
Dedication
Packt Upsell
Contributors
Preface
Index

Grouping results (aggregate functions)


You can group the results using the GROUP BY clause on a column and then use AGGREGATE functions, such as COUNT, MAX, MIN, and AVERAGE. You can also use the function on a column in a group by clause. See the SUM example where you will use the YEAR() function.

How to do it...

Each of the previously-mentioned aggregate functions will be introduced to you here in detail.

COUNT

  1. Find the count of male and female employees:
mysql> SELECT gender, COUNT(*) AS count FROM employees GROUP BY gender;
+--------+--------+
| gender | count  |
+--------+--------+
| M      | 179973 |
| F      | 120051 |
+--------+--------+
2 rows in set (0.14 sec)
  1. You want to find the 10 most common first names of the employees. You can use GROUP BY first_name to group all the first names, then COUNT(first_name) to find the count inside the group, and finally the ORDER BY count to sort the results. LIMIT these results to the top 10:
mysql> SELECT first_name, COUNT(first_name) AS count...