-
Book Overview & Buying
-
Table Of Contents
Swift 3 Object-Oriented Programming - Second Edition
By :
The { (game: Game) -> Bool in game.highestScore == highestScore && game.playedCount == playedCount } closure is equivalent to:
{ $0.highestScore == highestScore && $1.playedCount == playedCount }.
{ $0.highestScore == highestScore && $0.playedCount == playedCount }.
{ 0 -> 0.highestScore == highestScore && 0.playedCount == playedCount }.
The closure { return condition($0) } is equivalent to:
{ (number: Int) -> Bool in return condition(number) }.
{ (number -> Bool) -> Int in condition <- (number) }.
{ 0 -> condition(number) }.
A function type specifies:
The parameter and return types for the function.
Only the parameter names required for the function.
The required function name and the return value without any details about the parameters.
Which of the following lines declare a variable with a function type, considering that the syntax must be compatible with Swift 3?
var condition: { 0 -> Int -> Bool }.
var...