Book Image

Java Coding Problems - Second Edition

By : Anghel Leonard
Book Image

Java Coding Problems - Second Edition

By: Anghel Leonard

Overview of this book

The super-fast evolution of the JDK between versions 12 and 21 has made the learning curve of modern Java steeper, and increased the time needed to learn it. This book will make your learning journey quicker and increase your willingness to try Java’s new features by explaining the correct practices and decisions related to complexity, performance, readability, and more. Java Coding Problems takes you through Java’s latest features but doesn’t always advocate the use of new solutions — instead, it focuses on revealing the trade-offs involved in deciding what the best solution is for a certain problem. There are more than two hundred brand new and carefully selected problems in this second edition, chosen to highlight and cover the core everyday challenges of a Java programmer. Apart from providing a comprehensive compendium of problem solutions based on real-world examples, this book will also give you the confidence to answer questions relating to matching particular streams and methods to various problems. By the end of this book you will have gained a strong understanding of Java’s new features and have the confidence to develop and choose the right solutions to your problems.
Table of Contents (16 chapters)
1
Text Blocks, Locales, Numbers, and Math
Free Chapter
2
Objects, Immutability, Switch Expressions, and Pattern Matching
14
Other Books You May Enjoy
15
Index

28. Computing the square root of a number using the Babylonian method

Believe it or not, the ancient Babylonians (around 1500 BC) knew how to estimate square roots long before the popular method discovered by Newton.

Mathematically speaking, the Babylonian approach for estimating the square root of v > 0 is the recurrence relation from the following figure:

Figure 1.23.png

Figure 1.23: The recurrence relation of Babylonian square root approximation

The recurrence formula starts with an initial guess of x0. Next, we calculate x1, x2, …, xn by substituting xn-1 in the formula on the right-hand side and evaluating the expression.

For instance, let’s try to apply this formula to estimate the square root of 65 (the result is 8.06). Let’s start with x0 as 65/2, so x0 =32.5, and let’s calculate x1 as:

Having x1, we can calculate x2 as follows:

Having x2, we can calculate x3 as follows:

We are getting closer to the final result...