Book Image

Java Coding Problems - Second Edition

By : Anghel Leonard
Book Image

Java Coding Problems - Second Edition

By: Anghel Leonard

Overview of this book

The super-fast evolution of the JDK between versions 12 and 21 has made the learning curve of modern Java steeper, and increased the time needed to learn it. This book will make your learning journey quicker and increase your willingness to try Java’s new features by explaining the correct practices and decisions related to complexity, performance, readability, and more. Java Coding Problems takes you through Java’s latest features but doesn’t always advocate the use of new solutions — instead, it focuses on revealing the trade-offs involved in deciding what the best solution is for a certain problem. There are more than two hundred brand new and carefully selected problems in this second edition, chosen to highlight and cover the core everyday challenges of a Java programmer. Apart from providing a comprehensive compendium of problem solutions based on real-world examples, this book will also give you the confidence to answer questions relating to matching particular streams and methods to various problems. By the end of this book you will have gained a strong understanding of Java’s new features and have the confidence to develop and choose the right solutions to your problems.
Table of Contents (16 chapters)
1
Text Blocks, Locales, Numbers, and Math
Free Chapter
2
Objects, Immutability, Switch Expressions, and Pattern Matching
14
Other Books You May Enjoy
15
Index

20. Computing mathematical absolute value for int/long and result overflow

Mathematical absolute value is notated by placing the value between two pipe operators and is computed as follows:

|x| = x, |-x| = x

It is commonly used for computing/expressing distances. For example, imagine that 0 represents the sea level and we have a scuba diver and a climber. The scuba diver is underwater at -45 ft (notice that we use negative numbers to express how deep in the water the scuba diver is). At the same time, the climber has climbed 30 ft high. Which of them is closer to the sea level (0)? We may think that since -45 < 30, the scuba diver is closer because its value is smaller. However, we can easily find the correct answer by applying the mathematical absolute, as follows:

|-45| = 45, |30| = 30
45 > 30, so the climber is closer to the sea level (0)

Now, let’s dive into the solution with the following example:

int x = -3;
int absofx = Math.abs(x); // 3
...